time and distance Model Questions & Answers, Practice Test for ssc chsl tier 1 2023

Question :6

A man rows upstream 16 km and downstream 28 km, taking 5 hours each time. The velocity of the current is ________ km/hr.

Answer: (a)

Upstream speed = ${16}/5$ km/hr

Downstream speed = ${28}/5$ km/hr

∴ Velocity of current = ${{{28}/5}-{{16}/5}}/2 = {12}/{10}$= 1.2 km/hr

Question :7

A boat running downstream covers a distance of 16 km in 2 hours while for covering the same distance upstream, it takes 4 hours. What is the speed of the boat in still water?

Answer: (a)

Rate downstream

= $(16/2)$ kmph = 8 kmph;

Rate upstream

= $(16/4)$ kmph = 4 kmph.

∴ Speed in still water

= ${1/2}(8 + 4)$ = 6 km/h.

Question :8

The driver of a car driving @ 36 kmph locates a bus 40 meters ahead of him. After 20 seconds the bus is 60 meters behind. The speed of the bus is :

Answer: (d)

Net distance gained by car over the bus

= 40 + 60 = 100m, in 20 sec.

$Time= \text"Distance"/\text"Relative speed"$

⇒$20=100/{(36×{5/18})-S_2}$

⇒$S_2$ = 5 m/s = 18 kmph.

Question :9

The jogging track in a stadium as 726 m in circumference. Rakesh and Ismail start from the same point and walk in opposite direction at 4.5 kmph and 3.75 kmph respectively. They will meet for the first time in

Answer: (b)

Time= $14.5×5/18x+3.75×5/18×x=726$

1.25x + 1.04 x = 726

x = 317sec

= 5.28 min

Question :10

A Train which travels at the uniform rate of 10 m a second leaves Madras for Arconum at 7 a.m. At what distance from Madras will it meet a train which leaves Arconum for Madras at 7.20 a.m., and travels one-third faster than the former does, the distance from Madras to Arconum being 68 km?

Answer: (b)

$S_1 = 10 × {18}/5$ = 36 km/hr

$S_2 = 36 + {36}/3$ = 48 km/hr

∴ Difference in time = $T_1 – T_2$ = 7 am – 7.20 am = -$1/3$ hr

∴ Distance of meeting point from madras

=36$[{68-48(-1/3)}/{36+48}] = 36[{68 + 16}/{36 + 48}]$ = 36km

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